Läbi Minkowski taas Gallei liikumisteisendusse

E(x; y;) ;
f(E) = F;
Minkowski:
L(E) = (Lx; Ly);
Galilei:
f(L(E)) = (x*; y*); 
(1/k)(f(E)) = E(L)(x; y);
kL(f(E)) = F. k = 1/D, D on nn. LOrent´tegur.

Leppigem harimatusega,. kui see on objektiivne!

Please log in using one of these methods to post your comment:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Muuda )

Twitter picture

You are commenting using your Twitter account. Log Out / Muuda )

Facebook photo

You are commenting using your Facebook account. Log Out / Muuda )

Google+ photo

You are commenting using your Google+ account. Log Out / Muuda )

Connecting to %s